Posted by Jimmy on .
A ball, of mass 0.13Kg, is held on the inside of a smooth hemispherical bowl at a height 0.25 m above the base. It is then released. Assuming there is no friction, the acceleration due to gravity, g, is 10 m/s2 and the potential energy is zero at the base of the bowl - What is the speed of the ball at a height of 0.1 m above the base?
Use conservation of energy. For the correct answer, you need to include the rotational kinetic energy of the ball.
If the bowl is so smooth that the ball slides and does not roll, you can neglect rotational kinetic energy.
Classes that ask you to assume g has the incorrect value of 10 m/s^2 are doing a disservice to physics education and the students, in my opinion.