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If both masses are increased by 60% and the distance between them is halved, by what percent will the force of attraction increase?

  • physics (gravity) and math - ,

    Since the force is given by
    F = (constant)*M1*M2/R^2 ,

    The new force, after the changes, will be higher by a factor (1.6)^2/(0.5)^2 = 10.24

    That means there is a 924% increase.

    You do not have to know the actual masses and distances to make that conclusion.

    M1 and M2 are the two masses, and R is the distance between them.

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