Posted by **nam maurer** on Tuesday, November 22, 2011 at 6:59am.

a projectile has an initial velocity of 15.0 m/s at an angle of 30 degrees above the horizontal. What is the location of the projectile 2.0 seconds later?

- Physics -
**drwls**, Tuesday, November 22, 2011 at 7:20am
The time of flight of the projectle is

2 Vo*sin30/g = 1.53 seconds

After 2.0 seconds, it will have hit the ground already. Whether and how far it rolled after that I cannot say.

- Physics -
**JAMES**, Friday, November 4, 2016 at 12:05pm
X = (V COSĪ±)t

= 15*cos30*2

= 25.98

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