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a projectile has an initial velocity of 15.0 m/s at an angle of 30 degrees above the horizontal. What is the location of the projectile 2.0 seconds later?

  • Physics -

    The time of flight of the projectle is
    2 Vo*sin30/g = 1.53 seconds

    After 2.0 seconds, it will have hit the ground already. Whether and how far it rolled after that I cannot say.

  • Physics -

    X = (V COSĪ±)t
    = 15*cos30*2

    = 25.98

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