What is the distance between two parallel lines whose equation is L1,3x-4y+10=0 and L2,3x-4y+2=0
For a single line, Ax+By+C=0 the distance from a point (x0,y0) is
D=|(Ax0+By0+C)/sqrt(A^2+B^2)|
Hence for two lines, take the difference of the constant terms, and divide by S, the square-root of the sum of the squares of coefficients of x and y.
Difference of constant terms = 10-2=8
S = sqrt(3^2+4^2)=5
Distance between the two lines
= 8/5