Acid dissociation constant for HNO3+H2O-H3O+ +NO3=

I have [H3O+][NO1-3]/[HNO3]

Do I have this right?

yes

Identify the conjugate acid and based pair in the following.

HN03 +H20 =H30 + N03 .

Yes, you are on the right track. The expression you have written is indeed the correct expression for the acid dissociation constant of nitric acid (HNO3) in water (H2O), which can be represented as:

HNO3 + H2O ⇌ H3O+ + NO3-

The acid dissociation constant (Ka) is defined as the ratio of the concentration of the product ions (H3O+ and NO3-) multiplied together to the concentration of the reactant (HNO3). Therefore, the correct expression for Ka is:

Ka = [H3O+][NO3-] / [HNO3]

In this expression, the square brackets represent the concentration of the species in moles per liter (Molarity).

So, to calculate the Ka for a given concentration of H3O+, NO3-, and HNO3, you just need to plug in the respective values into the equation and perform the calculation.