Homework Help: Algebra II

Posted by Zach on Monday, November 21, 2011 at 9:54pm.

The volume of a given weight of gas varies directly as its absolute temperature t and inversely as its pressure p. If the volume is 4.45 m^3 when p=225 kilo pascals (kpa) and t = 305 K, find the volumn when p = 325 kpa and t = 354 k.

Algebra II - Steve, Tuesday, November 22, 2011 at 10:43am
v = kt/p

Find k:

4.45 = k * 305 / 225
k = 3.28

Now, find the new volume:

v = 3.28 * 354 / 325
v = 3.56

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