Posted by Alex on Monday, November 21, 2011 at 9:40pm.
f = 9x/(x^2 + 49)
f is concave up where f'' > 0
f' = -9(x^2 - 49) / (x^2 + 49)^2
f'' = 18x(x^2 - 147)/(x^2 + 49)^3
f'' < 0 where 0 < x < √147 or x < -√147
f'' > 0 where -√147 < x < 0 or x > √147
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