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September 18, 2014

September 18, 2014

Posted by **Alex** on Monday, November 21, 2011 at 9:40pm.

f(x)=9x/x^2+49

- calculus -
**Steve**, Tuesday, November 22, 2011 at 10:36amf = 9x/(x^2 + 49)

f is concave up where f'' > 0

f' = -9(x^2 - 49) / (x^2 + 49)^2

f'' = 18x(x^2 - 147)/(x^2 + 49)^3

f'' < 0 where 0 < x < √147 or x < -√147

f'' > 0 where -√147 < x < 0 or x > √147

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