You leave a 20.0ml of 6.00m HCl on the counter. If 7.00ml of water evaporates out of container overnight. Whats the new molarity?
Is that 6.00m or 6.00M?
6.00M HCl
I got 17.14= 17.1M. Is this correct? Thank you
To determine the new molarity of the HCl solution after the evaporation, we need to consider the change in volume caused by the evaporation of water.
First, let's calculate the initial number of moles of HCl in the 20.0 ml solution using the formula:
moles = molarity × volume (in liters)
Molarity of the initial solution (before evaporation) = 6.00 M
Volume of the initial solution (before evaporation) = 20.0 ml = 0.020 L
The initial number of moles of HCl = 6.00 M × 0.020 L = 0.12 moles
Next, we need to determine the final volume of the solution after the evaporation. Since 7.00 ml of water has evaporated, the final volume will be:
Final volume = Initial volume - Evaporated volume = 20.0 ml - 7.00 ml = 13.0 ml = 0.013 L
Finally, we can calculate the new molarity using the formula:
Molarity = moles / volume (in liters)
New molarity = 0.12 moles / 0.013 L ≈ 9.23 M
Therefore, the new molarity of the HCl solution after 7.00 ml of water evaporates overnight is approximately 9.23 M.