Posted by James on Monday, November 21, 2011 at 2:11pm.
100 m
let the time at which was at the 800 m mark be t
then Fran's rate = 800/t
Dan's rate = 300/t
Let the time it took Fran to run the whole 1000 m be k
1000 = k(800/t)
k = 1000t/800
in that same time of k, distance covered by Dan was
D = k(300/t) , using Distance = rate x time
= (1000t/800)(300/t) = 375
so Dan is still 625 m from the finish line when Fran crosses.
I think I misread the question.
Dan was 300 m from the finish line, so he had gone 700 m, I took it that he went 300 m
so change all my 300's to 700
D = (1000t/800)(700/t) = 875
so he was 125 m from the finish line.
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