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September 2, 2014

September 2, 2014

Posted by **James** on Monday, November 21, 2011 at 2:11pm.

- Math -
**Ms. Sue**, Monday, November 21, 2011 at 2:18pm100 m

- Math -
**Reiny**, Monday, November 21, 2011 at 2:33pmlet the time at which was at the 800 m mark be t

then Fran's rate = 800/t

Dan's rate = 300/t

Let the time it took Fran to run the whole 1000 m be k

1000 = k(800/t)

k = 1000t/800

in that same time of k, distance covered by Dan was

D = k(300/t) , using Distance = rate x time

= (1000t/800)(300/t) = 375

so Dan is still 625 m from the finish line when Fran crosses.

- correction - Math -
**Reiny**, Monday, November 21, 2011 at 3:28pmI think I misread the question.

Dan was 300 m from the finish line, so he had gone 700 m, I took it that he went 300 m

so change all my 300's to 700

D = (1000t/800)(700/t) = 875

so he was 125 m from the finish line.

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