Posted by Anonymous on Monday, November 21, 2011 at 1:31pm.
What did you use for Eo Zn and Eo Co?
I don't know why you have anything with k since k is not given.
Using -0.762 for Zn and -0.28 for Co, I obtained about 0.48v for Ecell.
EZn = EoZn -(0.0592/2)*log(1/0.21) = about -0.78; then note that this is in the cell as an oxidation so change that to +0.78v
ECo = -0.28 -(0.0592/2)*log(1/0.21) = about -0.30.
Then Ecell = Eox + Ered = 0.78-0.30=0.48v
Check my work.
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