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March 4, 2015

March 4, 2015

Posted by **Joy** on Monday, November 21, 2011 at 1:31pm.

- Algebra II -
**Reiny**, Monday, November 21, 2011 at 2:49pmI am going to ignore your formula, since the variables are not defined, instead your problem becomes

50000(1.15)^t = 70000

1.15^t = 1.4

log (1.15^t) = log 1.4

t log 1.15 = log 1.4

t = log 1.4/log 1.15 = 2.4 = 2 years and about 5 months

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