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December 18, 2014

December 18, 2014

Posted by **Joy** on Monday, November 21, 2011 at 1:29pm.

p=30.0e^-kh

where k=3.83*10^-5. At what height will the pressure be 10.0 in. of mercury.

- Algebra II -
**Reiny**, Monday, November 21, 2011 at 2:57pmI assume h is the height, so

30 e^(-kh) = 10

e^(-kh) = 1/3

- kh = ln (1/3)

-kh = -1.098612...

h = 1.098612/k = 28684.4

check:

30 ( e^(-.0000383(28684.4))

= 30(.3333333) = 9.9999997 , not bad

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