Monday

December 22, 2014

December 22, 2014

Posted by **Joy** on Monday, November 21, 2011 at 1:14pm.

i=6.25e^-125t (amperes)

where t is the time in seconds. At what time will the current be 1.00 A?

- Algebra II -
**Damon**, Monday, November 21, 2011 at 1:19pm1/6.25 = e^-(125 t)

.16 = e^-(125 t)

ln .16 = -125 t

-1.83 = -125 t

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