A sample of gas at 1.3 atm of pressure is in a 2.0 L container. What will the pressure be if the sample is transferred to a 0.90 L container?
1. 0.59 atm 2. 1.4 atm 3. 2.9 atm 4. 3.2 atm
P1V1 = P2V2
3.2 atm
2.9 atm
To solve this question, we can use the ideal gas law equation: PV = nRT.
Given:
P1 = 1.3 atm (initial pressure)
V1 = 2.0 L (initial volume)
V2 = 0.90 L (final volume)
To find the final pressure (P2), we can use the formula:
P1 * V1 = P2 * V2
Plugging in the values we know:
1.3 atm * 2.0 L = P2 * 0.90 L
Now we can solve for P2:
P2 = (1.3 atm * 2.0 L) / 0.90 L
P2 = 2.9 atm
Therefore, the answer is option 3: 2.9 atm.