A sample of gas at 1.3 atm of pressure is in a 2.0 L container. What will the pressure be if the sample is transferred to a 0.90 L container?

1. 0.59 atm 2. 1.4 atm 3. 2.9 atm 4. 3.2 atm

P1V1 = P2V2

3.2 atm

2.9 atm

To solve this question, we can use the ideal gas law equation: PV = nRT.

Given:
P1 = 1.3 atm (initial pressure)
V1 = 2.0 L (initial volume)
V2 = 0.90 L (final volume)

To find the final pressure (P2), we can use the formula:

P1 * V1 = P2 * V2

Plugging in the values we know:

1.3 atm * 2.0 L = P2 * 0.90 L

Now we can solve for P2:

P2 = (1.3 atm * 2.0 L) / 0.90 L

P2 = 2.9 atm

Therefore, the answer is option 3: 2.9 atm.