Homework Help: chemistry

Posted by Anonymous on Monday, November 21, 2011 at 10:17am.

Calculate the partial pressure (in atm) of propane in a mixture that contains equal weights of propane (C3H8) and butane (C4H10) at 18°C and 746 mmHg

chemistry - DrBob222, Monday, November 21, 2011 at 1:43pm
P_propane = X_propane*P_total
P_{total = 746/760 = ?atm (the problem asks for atm).

So all we need to do is to determine X_propane and plug into the above.

molar mass C3H8 = about 44

molar mass C4H10 = about 58. YOu can do all of this more accurately.

X_propane = (g/44)/[(g/44)+(g/58)]

Solve for X and substitute into the above. I get something like 420 mm (but the problem asks for atm).}

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