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September 18, 2014

September 18, 2014

Posted by **nelo** on Monday, November 21, 2011 at 9:12am.

- physics -
**drwls**, Monday, November 21, 2011 at 10:37amHis "launch angle" is

theta = cos^-1(33/35) = 19.46 degrees

The initial vertical velocity component is

Voy = 35*sin(19.46)

= 11.66 mph

= 17.1 ft/s

The time to reach maximum height is

t' = (Voy)/g = 0.53 seconds

Maximum height = (1/2)*Voy*t' = 4.5 feet PLUS the initial ramp height where he leaves it. They should have told you what that is.

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