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March 3, 2015

March 3, 2015

Posted by **Rychelle** on Monday, November 21, 2011 at 8:55am.

- Physics -
**drwls**, Monday, November 21, 2011 at 10:47amThe range R of the jump must be R = 4m, if the waterfall were not there. That correspopnds to a distance to maximum height (the waterfall top) of 2 m.

Using the equation for range:

(R/2) = (1/2)*Vo^2*sin(2A)/g = 2 m

Vo^2 = 21.8 m/s

Vo = 4.7 m/s

A is the launch angle. It gets doubled because 2sinA*cosA = sin(2A) appears in the equation for R.

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