Saturday
April 19, 2014

Homework Help: Calculous

Posted by Yoona on Monday, November 21, 2011 at 8:46am.

A dunction is continious on the closed interval [-3,3] such that of f(-3)=4 and f(3)=1. The functions F' anf F'' have the properties shown below

Ok there's supposed to be a table but you cant really see it

-3<x<-1
F'(x) is positive
F''(X) is positive

X=-1
f'(x)and f''(x) failed to exist
-1<x<1
f'(x) is negative
f''(x) is positive

x=0
F'(x) and f''(x) are 0

1<x<3 f'(x) and f''(x) are negative



a) what are the x-coordinates of all the absolute maxes and minimu points of f on the inerval [-3,3] Justify your answer

b)what are the x-coordinateds of all points of inflection of f on the interval [-3,3]? Justify your answer

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculous - let f be the function defined by |x-1|+2 for X<1 f(x)= ax^2-Bx, ...
AP Calculous - let f be the function defined by |x-1|+2 for X<1 f(x)= ax^2-Bx...
math: real numbers - The statement below is false. Correct it by changing two ...
AP Calculous - let f be the function defined by f(x)=3X^5 -5X^3 +2 a) on what ...
calculus(QUICK QQUESTION!!) - if f(t) were continious on the interval [-2,1] but...
Math - Can someone explain to me.... when you are graphing number sets.... when ...
Calculus - 1. Locate the absolute extrema of the function f(x)=cos(pi*x) on the ...
Calculus IVT - The function f is continuous on the closed interval [0,6] and ...
Minimum on a Closed Interval - What is the minimum value of the function g(x)= 1...
calculus - The function f is continuous on the closed interval [0,2] and has ...

Search
Members