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given tanθ= -2√10/3 and π/2<θ< π find:


b.tan θ/2

could some1 help me with these 2 they're the only ones i couldn't get

  • mathematics -

    OK so it is in the second quadrant and the reference angle is arctan 2√10/3.
    The ref. angle is arctan2.1082 = 64.6 degrees.
    The angle itself is 180 -64.6 = 115.4 degrees = 2.0137 radians.

    use that to compute (a) and (b)

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