Posted by **Yuli** on Monday, November 21, 2011 at 4:44am.

given sinθ=-5/13 and π<θ<3π/2 find

sin2θ

cos( θ-4π/3)

sin(θ/2)

can some1 please help me with this?

- mathematics -
**Steve**, Monday, November 21, 2011 at 5:13am
Let's go through this again.

θ is in the 3rd quadrant, so x and y are both negative, and the hypotenuse h = 13

sinθ = -5/13

cosθ = -12/13

Use these values in your half-angle and double-angle and sum/difference formulas.

sin 2θ = 2 sinθ cosθ = 2(-5/13)(-12/13) = 120/169

cos(θ-4π/3) = cosθ cos4π/3 + sinθ sin4π/3

= (-12/13)(-1/2) + (-5/13)(-√3/2)

= 12/26 + 5√3/26

sin θ/2 = √((1-cosθ)/2)

= √((1 + 12/13)/2)

= √(25/26)

Use this same method for all your other similar problems.

## Answer This Question

## Related Questions

- trigonometry - given tanθ= -2√10/3 and π/2<θ< π ...
- math - given sinθ=-5/13 and π<θ<3π/2 find sin2θ ...
- Precalc/Trig - Sorry there are quite a few problems, but I just need to know if ...
- trig - cosθ =5/13 with -π/2 < θ <0 find each of the ...
- trigonometry - if cosθ=2/3 and tanθ<0 find the exact value sin(&#...
- math - if cosθ=2/3 and tanθ<0 find the exact value sin(θ-5&#...
- Math - Calculus - The identity below is significant because it relates 3 ...
- trigonometry - tanθ= -2sqrt10/3 and π/2<θ< π find a. ...
- TRIGONOMETRY - Can you check my work, please? This is for a trig study guide for...
- mathematics - given tanθ= -2√10/3 and π/2<θ< π ...

More Related Questions