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posted by on .

find L- Hospital

lim x_---- inf 1/e^(-x)=

  • calculus - ,

    You don't need L'Hopital's rule for that limit.

    1/e^(-x) = e^x
    and that goes to infinity as x-> infinity.

    Are you sure you copied the question correctly?

  • calculus - ,

    limxexsitat2 -4x+3/xsquer-1

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