Posted by Josh on Monday, November 21, 2011 at 1:27am.
We see right off that x=0 is a root.
Any rational roots must have a numerator which divides 3, and a denominator which divides 3. So, try 3,1,1/3
Then we have x(x-1)(3x^2 - 8x + 3)
The quadratic formula reveals the other two roots:
4/3 +/- √7/3
_____________________
If 2+i is a root, so is 2-i, so x^2 -4x + 5 is a factor.
So, f(x) = (x-1)(x-1)(x^2 - 4x + 5)
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