Posted by **momo** on Monday, November 21, 2011 at 1:07am.

How do I create a quadratic equation that passes through the points (-1,2),(1,7),(4,5)?

- Math -
**Anonymous**, Monday, November 21, 2011 at 1:53am
y = a x ^ 2 + b x + c

In this case:

For x = - 1 , y = 2

2 = a ( - 1 ) ^ 2 + b ( - 1 ) + c

a - b + c = 2

For x = 1 , y = 7

7 = a ( 1 ) ^ 2 + b 1 + c

a + b + c = 7

For x = 4 , y = 5

5 = a ( 4 ) ^ 2 + b 4 + c

16 a + 4 b + c = 5

So you must solve system of 3 equations :

a - b + c = 2

a + b + c = 7

16 a + 4 b + c = 5

The exact solutions are :

a = - 19 / 30

b = 5 / 2

and

c = 77 / 15

y = ( - 19 / 30 ) x ^ 2 + ( 5 / 2 )x + 77 / 15

## Answer this Question

## Related Questions

- Algebra - How do I create a quadratic equation that passes through the points (-...
- Math - (1 & 2) The first three points do not fall on a straight line, and there ...
- Math Question - Laura was given two points (3,-2) and (-2,4) and was asked to ...
- mat 101 - Equation for a line that passes through (6,26) and has a slope of 3 ...
- Math 101 - Find the equation for each of the following items below: a. A line ...
- Maths - It is given a quadratic function y=a(x-h)62+k.If its graph is a parabola...
- Math - This question concerns the straight line that passes through the points...
- Math (Algebra) - Consider the graph of the quadratic function y=ax^2+bx+c. If it...
- math - i have more than one question so if u no any of the answers please tell ...
- math - find the exponential function of the form y=ab^x whose graph passes ...

More Related Questions