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December 19, 2014

December 19, 2014

Posted by **Linda** on Sunday, November 20, 2011 at 10:54pm.

1) 2+5i/5+2i

2) 6-i√2/6+i√2

for the first one I solved it and I only got this far: 10+21i-10i^2/25-4i^2

- Algebra 2 -
**Steve**, Sunday, November 20, 2011 at 11:38pmRemember that i^2 = -1

25-4i^2 = 25+4 = 29

10 + 21i - 10i^2 = 10 + 21i + 10 = 20 + 21i

So, you have (20 + 21i)/29 = 20/29 + 21/29 i

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