Draw a block and tackle system of pulleys with a velocity ratio of 5 is used to raise a mass of a 25kg through a vertical distance of 40cm at a steady rate.
Data
VR=5
Work done=25kg
L=40cm
Effort=60N
Draw a block and tackle system of pulley with a velocity ratio of 5. A block tackle, with a velocity ration of 5 used to raise a mass of 25k. through a vertical distance of 40CM a stead by rate if the effort is equal to 60N determine
A= the distance moved by the effort
B= the work done by the effort in lifting the load
C= the loss in energy involved in operating the machine.
V.R=De/DL
De=V.r×Dl
=5×40
=200cm=2m
Sure! To draw a block and tackle system of pulleys with a velocity ratio of 5, we need to understand the basic concept of a block and tackle system.
A block and tackle system consists of multiple pulleys arranged in a specific configuration to multiply the force applied to lift a load. It typically comprises a combination of fixed and movable pulleys.
In this case, we want to create a system with a velocity ratio of 5. The velocity ratio is the ratio of the distance the effort (the force applied) moves to the distance the load (the mass being lifted) moves. A velocity ratio of 5 means that for every 5 centimeters the effort moves, the load will move 1 centimeter.
To draw the block and tackle system, follow these steps:
1. Start by drawing a fixed pulley at the top. This is a pulley that is attached to a support and does not move. Label it as "Pulley A."
2. Below Pulley A, draw two movable pulleys side by side. Label them as "Pulley B" and "Pulley C." These pulleys will be attached to the load and move along with it.
3. From Pulley B and Pulley C, draw two separate ropes hanging down vertically. These ropes will be connected and looped around another movable pulley. Label this pulley as "Pulley D."
4. Connect the ends of the ropes from Pulley B and Pulley C to Pulley D. This configuration creates a mechanical advantage and allows the load to be lifted more easily.
5. Finally, draw the load as a rectangle below Pulley D and label it as "25kg."
Now that we have the visual representation of the block and tackle system, let's calculate the effort needed to raise the load.
The velocity ratio of 5 means that for every 5 cm the effort moves, the load will move 1 cm. In our case, the load needs to be raised by 40 cm at a steady rate. Therefore, the effort needs to be moved (5 * 40) cm, which equals 200 cm.
To calculate the effort required, we can use the formula:
Effort = Load / Velocity Ratio
Effort = 25 kg / 200 cm = 0.125 kg/cm
So, in this case, an effort of 0.125 kg/cm is needed to raise the load of 25 kg through a vertical distance of 40 cm at a steady rate with a block and tackle system having a velocity ratio of 5.