A particle moves along the c-axis so that at time t its position is given by x(t)=t^2-6^t+9t+11
a)What is the velocity of the particle at t=0
b)During what time intervals is the particle moving to the left?
c)What is the total distance traveled by the particle t=0 to t=2
Calculus - Correction? - Steve, Sunday, November 20, 2011 at 2:53pm
I can't believe that is the correct equation of motion. 6^t will grow negative quite quickly. Since there's a typo in c-axis, I suspect there's another in the equation.
Calculous - Yoona, Sunday, November 20, 2011 at 2:55pm
opps it is x(t)=t^3-6t^2+9t+11
Calculus - Steve, Sunday, November 20, 2011 at 4:09pm
x(t) is the position
x'(t) is the velocity
x'(t) = 3t^2 - 12t + 9
x'(0) = 9
particle moving to the left means velocity is negative.
3(t^2 - 4t + 3) = 3(t-1)(t-3) < 0
when 1 < t < 3
distance traveled is x(2) - x(0)
Calculous - Yoona, Sunday, November 20, 2011 at 4:55pm
thanks!!! that was VERY helpful!!