Posted by **taylor** on Sunday, November 20, 2011 at 1:36pm.

a model rocket rises with constant accerleration to a height of 3.2 m, at which point its speed is 26.0 m/s. (a) how much time does it take for the rocket to reach this height? (b) what was the magnitude of the rocket's acceration? (c) find the height and speed of the rocket 0.10 s after launch.

- phyics (PLEASE PLEASE READ) -
**Henry**, Monday, November 21, 2011 at 4:37pm
a. VF^2 = Vo^2 + 2g*d,

Vo^2 = Vf^2 - 2g*d,

Vo^2 = (26)^2 + 19.6*3.2 = 738.72,

Vo = 27.18m/s.

t = (Vf - Vo) / g,

t = (26 - 27.18) / -9.8 = 0.12s.

b.

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