Posted by **Brianna ** on Sunday, November 20, 2011 at 12:24pm.

(ex)x·e4x + 4 = 1… so i need to solve for x…. how the hell do I do that???

- College Algebra -
**Brianna **, Sunday, November 20, 2011 at 12:26pm
Hey sorry the equation is a little different than that…

(ex)x·e4x + 4 = 1

all the xs and 4x+4 are all exponents.

- College Algebra -
**Steve**, Sunday, November 20, 2011 at 12:33pm
If you mean e^x * e^(4x+4) = 1

just take log of both sides:

x + (4x+4) = 0

5x = -4

x = -4/5

check

e^(-4/5) * e^(-16/5 + 20/5) = e^(-4/5) * e^(4/5) = e^(-4/5 + 4/5) = e^0 = 1

## Answer This Question

## Related Questions

- College Algebra - Solve the following equation in the complex number system x^4+...
- college algebra - Need to solve what are the steps to do so? 1.5<9.1-0.5x<...
- college algebra - 2x+y=-2 (1) x+y-z=-4 (2) 3x+5y+z=0 (3) solve the system need ...
- College Algebra..LOG - log4(little four) (40 - 3x) = 0 now i need to solve for ...
- College Algebra..LOG - log4(little four) (40 - 3x) = 0 now i need to solve for x...
- division of fractions - Division of fractions is sometimes said to be ...
- college algebra - 12x+4y+2z=-7 (1) 3x-12y+6z=-4 (2) 9x-16y+4z=-3 (3) solve the ...
- college algebra - 2/5(5x-3) - 1/3(12x-5). Have the correct answer but need ...
- college algebra - How do you solve f(x)=square root of 2x+1 using the difference...
- college algebra--I really need help!! - solve the following exponential equation...

More Related Questions