Posted by **Brianna** on Sunday, November 20, 2011 at 12:24pm.

(ex)x·e4x + 4 = 1… so i need to solve for x…. how the hell do I do that???

- College Algebra -
**Brianna**, Sunday, November 20, 2011 at 12:26pm
Hey sorry the equation is a little different than that…

(ex)x·e4x + 4 = 1

all the xs and 4x+4 are all exponents.

- College Algebra -
**Steve**, Sunday, November 20, 2011 at 12:33pm
If you mean e^x * e^(4x+4) = 1

just take log of both sides:

x + (4x+4) = 0

5x = -4

x = -4/5

check

e^(-4/5) * e^(-16/5 + 20/5) = e^(-4/5) * e^(4/5) = e^(-4/5 + 4/5) = e^0 = 1

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