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October 1, 2014

October 1, 2014

Posted by **Tracy** on Sunday, November 20, 2011 at 9:15am.

xe^2x(dx)

A. (1/6)(x^2)(e^3x)+C

B. (1/2)(xe^2x)-(1/2)(e^2x)+C

C. (1/2)(xe^2x)-(1/4)(e^2x)+C

D. (1/2)(x^2)-(1/8)(e^4x)+C

- calculus -
**Damon**, Sunday, November 20, 2011 at 10:25amu dv = u v - int v du

u = x

du = dx

dv = e^(2x) dx

v = (1/2) e^(2x)

so

int x e^(2x) dx = (x/2)e^(2x)- int (1/2)e^(2x) dx

= (x/2)e^(2x)- (1/4)e^(2x) +c

so I think C.

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