xe^2x(dx) A. (1/6)(x^2)(e^3x)+C B. (1/2)(xe^2x)-(1/2)(e^2x)+C C. (1/2)(xe^2x)-(1/4)(e^2x)+C D. (1/2)(x^2)-(1/8)(e^4x)+C
u = x du = dx dv = e^(2x) dx v = (1/2) e^(2x) so int x e^(2x) dx = (x/2)e^(2x)- int (1/2)e^(2x) dx = (x/2)e^(2x)- (1/4)e^(2x) +c so I think C.
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