posted by Lee on .
I'm having a had time with this problem. Could you please help with step by step resolution?
e^-x / e^-1 + 3 dx
The "dx" at the end makes me think you are supposed to integrate
[e^-x / e^-1] + 3 .
But that would make it a calculus, not a precalculus, question.
It is not clear what the question is. In any case,
e^-x / e^-1 = e^(1-x)
The integral of
e^(1-x) + 3 dx is
-e^(1-x) + 3x + C
Thank you. You helped greatly.