a solution of sulphuric acid is titrated (allquot 20.0ml) with a solution of sodium hydroxide (0.1234M) 26.73ml of the base being required to the end point with phenolphthalein. calculate the molarity of the sulphuric acid solution

2NaOH + H2SO4 ==> 2H2O + Na2SO4

moles NaOH = M x L = ?
Convert moles NaOH to moles H2SO4 by using the coefficients in the balanced equation. That will be
?moles NaOH x (1 mole H2SO4/2 moles NaOH) = ?moles NaoH x (1/2) = x moles H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4.

To calculate the molarity of the sulphuric acid solution, we can use the concept of stoichiometry and the volume and concentration of the sodium hydroxide solution.

Here's the step-by-step approach to finding the molarity of the sulphuric acid solution:

1. Write the balanced chemical equation for the reaction between sulphuric acid (H2SO4) and sodium hydroxide (NaOH):
H2SO4 + 2NaOH → Na2SO4 + 2H2O

2. Determine the stoichiometric ratio between sulphuric acid and sodium hydroxide from the balanced equation. In this case, it is 1:2. This means that one mole of sulphuric acid reacts with two moles of sodium hydroxide.

3. Calculate the number of moles of sodium hydroxide used in the titration:
Moles of NaOH = Concentration of NaOH × Volume of NaOH solution
= 0.1234 M × 26.73 ml
= 0.003298 moles of NaOH

4. Using the stoichiometric ratio from step 2, we can determine the number of moles of sulphuric acid that reacted:
Moles of H2SO4 = 0.003298 moles of NaOH × (1 mole H2SO4 / 2 moles NaOH)
= 0.001649 moles of H2SO4

5. Calculate the molarity of the sulphuric acid solution:
Molarity = Moles of H2SO4 / Volume of H2SO4 solution (in liters)
= 0.001649 moles / (20.0 ml / 1000)
= 0.08245 M (rounded to five decimal places)

Therefore, the molarity of the sulphuric acid solution is approximately 0.08245 M.