Posted by **mack** on Saturday, November 19, 2011 at 5:14pm.

the centers of two 5000 kg blocks are seperated by 1.13 m.

What is the gravitational force between the two blocks?

What must be the distance between the centers of the blocks if the gravitational force decreases 25 times?

- physics -
**drwls**, Saturday, November 19, 2011 at 5:30pm
(1) F = G*M1*m2/R^2 = G *(5000)^2/(1.13)^2

Look up the value of G and compute.

(2) Five times more than 1.13 m, because of the inverse square dependence upon distance. .

- physics -
**mack**, Saturday, November 19, 2011 at 5:46pm
I have the formula down ok. My problem is with the exponents. G = 6.67 x 10^-11. M1 and m2 = 25,000,000. I wrote down m1 and m2 as 2.5 x 10^7. I multiplied 6.67 by 2.5 and come out with 16.67. I do not know why but I know I need to move the decimal point over and come up with 1.6675 x 10^3. My denomenator comes up to 1.2769. Does this sound right?

## Answer this Question

## Related Questions

- Physics - Three identical blocks, A, B, and C, are on a horizontal frictionless ...
- Physics-Mechaincs - A force of 23.52 N pushes and pulls to blocks as shown in ...
- physics - A series of two 2.0 kg blocks are attached together through string B....
- physics - A series of two 2.0 kg blocks are attached together through string B....
- Physics - Two blocks, with masses M1 = 1.4 kg and M2 = 9.9 kg, and a spring with...
- Physics - Two blocks are in contact on a frictionless table. A horizontal force ...
- Physics - Two blocks are in contact on a frictionless table. A horizontal force ...
- Physics - Two blocks are in contact on a frictionless table. A horizontal force ...
- Physics - Two blocks are in contact on a frictionless table. A horizontal force ...
- Physics - Two blocks are in contact on a frictionless table. A horizontal force ...

More Related Questions