Wednesday
August 27, 2014

Homework Help: Pre-Calculus

Posted by Stacy on Saturday, November 19, 2011 at 4:18pm.

This is application question.
Bacterial Control. If t days after treatment the bacteria count per cubic centimeter in a body of water is given by C(t) = 10t^2 - 120x + 800
0 <= t <= 9
Thn in how many days will the jcount be a minimum?

I got this result:

20(t^2 - 6 + 40)
20(t - 5)(t - 8)
t - 5 = 0 t - 8 = 0
t = 5 t = 8
f(5) = 700
f(8) = 1120
f(0) = 800
f(9) = 1340

20(3)^2-120(3)+800
500-600+800 = 700

20(8)^2-120(8)+800
1280-960+800 = 1120

20(0)^2-120(0)+800 = 800

20(9)^2-120(9)+800 =1340

minimum = 700

but this is incorrect. What am I doing wrong and how do I solve it?

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