Posted by **meagan** on Saturday, November 19, 2011 at 2:26pm.

Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring constant of spring 1 is 155 N/m. The motion of the object on spring 1 has twice the amplitude as the motion of the object on spring 2. The magnitude of the maximum velocity is the same in each case. Find the spring constant of spring 2.

- physics help! -
**drwls**, Saturday, November 19, 2011 at 5:37pm
Maximum velocity = w * (amplitude)

w is the angular frequency sqrt (k/m)

If the maximum velocities are the same, and object 1 has twice the amplitude, then its angular frequency must be half that of object 2. The natural frequency of object 2 is twice that of object 1.

Since the masses are equal, k is 4 times higher for object 2, or 620 N/m

## Answer This Question

## Related Questions

- phyics - Objects of equal mass are oscillating up and down in simple harmonic ...
- physics - Objects of equal mass are oscillating up and down in simple harmonic ...
- physics - 1. a 2 kg body is attatched to a spring of negligible mass and ...
- Physics - An object with mass 5.0 kg is attached to a spring with spring ...
- Physics - An object with mass 5.0 kg is attached to a spring with spring ...
- Physics - An object with mass 3.7 is attached to a spring with spring stiffness ...
- College Physics - Answer the following questions for a mass that is hanging on a...
- physics - An object with mass 2.0kg is attached to a spring with spring ...
- Physics - The period of motion of an object-spring system is T = 0.474 s when an...
- physics - When an object of mass m1 is hung on a vertical spring and set into ...

More Related Questions