Tuesday

March 31, 2015

March 31, 2015

Posted by **Tracy** on Saturday, November 19, 2011 at 2:12pm.

dx/square root of 9-8x-x^2

- Calculus -
**Steve**, Saturday, November 19, 2011 at 2:27pm9-8x-x^2 = 25 - (16 + 8x + x^2) = 3^2 - (x-4)^2

Integral sqrt(a^2 - u^2) du = u/2 * sqrt(a^2 - u^2) + a^2/2 arcsin(u/a)

just plug in a=5 and u=x-4 and plug away.

This is a standard trig substitution and integration by parts.

- Calculus -
**Steve**, Saturday, November 19, 2011 at 2:28pmtypo: 5^2 not 3^2

- Calculus -
**Bosnian**, Saturday, November 19, 2011 at 2:29pmGo on: wolframalpha dot com

When page be open in rectangle type:

integrate dx/sqrt(9-8x-x^2)

and click option =

After few seconds when you see result click option: Show steps

**Answer this Question**

**Related Questions**

Calculus - Evaluate the integral. The integral from 0 to the square root of 2 ...

Calculus - Find the exact area of the region enclosed by the square root of (x...

calculus - how do you solve the integral of 1/[(square root of x)(lnx)] from 2 ...

Calculus - Evaluate the integral from 0 to 24 of the square root of 9+3x dx.

Calculus - Evaluate the integral. The integral from the square root of three ...

Calculus - Evaluate integral of x times square root of (2x-1)dx

Calculus - Evaluate the integral from [(2/square rt 2),0] of dx/sqaure root of (...

Calculus - (integral) e^3x dx A. e^3x+C B. 1/3e^3x+C C. e^4x+C D. 1/4e^4x+C ...

Calculus - can you show me the steps to evaluate this indefinite integral. s(e/x...

Calculus - I'm not sure what to substitute in this question. Evaluate the ...