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Posted by on Saturday, November 19, 2011 at 2:12pm.

evaluate the integral of

dx/square root of 9-8x-x^2

  • Calculus - , Saturday, November 19, 2011 at 2:27pm

    9-8x-x^2 = 25 - (16 + 8x + x^2) = 3^2 - (x-4)^2

    Integral sqrt(a^2 - u^2) du = u/2 * sqrt(a^2 - u^2) + a^2/2 arcsin(u/a)

    just plug in a=5 and u=x-4 and plug away.

    This is a standard trig substitution and integration by parts.

  • Calculus - , Saturday, November 19, 2011 at 2:28pm

    typo: 5^2 not 3^2

  • Calculus - , Saturday, November 19, 2011 at 2:29pm

    Go on: wolframalpha dot com

    When page be open in rectangle type:

    integrate dx/sqrt(9-8x-x^2)

    and click option =

    After few seconds when you see result click option: Show steps

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