Posted by **Tracy** on Saturday, November 19, 2011 at 2:12pm.

evaluate the integral of

dx/square root of 9-8x-x^2

- Calculus -
**Steve**, Saturday, November 19, 2011 at 2:27pm
9-8x-x^2 = 25 - (16 + 8x + x^2) = 3^2 - (x-4)^2

Integral sqrt(a^2 - u^2) du = u/2 * sqrt(a^2 - u^2) + a^2/2 arcsin(u/a)

just plug in a=5 and u=x-4 and plug away.

This is a standard trig substitution and integration by parts.

- Calculus -
**Steve**, Saturday, November 19, 2011 at 2:28pm
typo: 5^2 not 3^2

- Calculus -
**Bosnian**, Saturday, November 19, 2011 at 2:29pm
Go on: wolframalpha dot com

When page be open in rectangle type:

integrate dx/sqrt(9-8x-x^2)

and click option =

After few seconds when you see result click option: Show steps

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