Posted by Tracy on Saturday, November 19, 2011 at 2:12pm.
evaluate the integral of
dx/square root of 9-8x-x^2
- Calculus - Steve, Saturday, November 19, 2011 at 2:27pm
9-8x-x^2 = 25 - (16 + 8x + x^2) = 3^2 - (x-4)^2
Integral sqrt(a^2 - u^2) du = u/2 * sqrt(a^2 - u^2) + a^2/2 arcsin(u/a)
just plug in a=5 and u=x-4 and plug away.
This is a standard trig substitution and integration by parts.
- Calculus - Steve, Saturday, November 19, 2011 at 2:28pm
typo: 5^2 not 3^2
- Calculus - Bosnian, Saturday, November 19, 2011 at 2:29pm
Go on: wolframalpha dot com
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