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Need help with the following along with all steps.

Find y" for y = 3x + 4/x

  • Pre-Calculus -

    write it as

    y = 3x + 4x^-1

    y' = 3 - 4x^-2
    y'' = 8x^-3 or 8/x^3

  • Pre-Calculus -

    Thank you so much for your help. Now that I look at it more closely. I understand what I wasn't seeing!

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