chemistry
posted by saud on .
calculate the halflife of a first order reaction if the concentration of the reactant is 0.0396 M at 12 seconds after the reaction starts and is 0.00579 M at 47 after the reaction starts. How long does it take for the reactant concentration to decrease to 0.00269 M

ln(No/N) = kt
No = 0.0396
N = 0.00579
k = solve
t = 4712 = 35 seconds.
Solve for k, then
k = 0.693/t_{1/2} and solve for t_{1/2}
Then
ln(No/N) = kt and plug in the new numbers to find time for the 0.00269M to be reached.