referring to the previous problem, if you had entered the same sandy patch with a lower speed, say 7.0 m/s, would the patch have the same effect on your speed, say 7.0 m/s, would the patch have the same effect on your speed? that is, assuming the sandy patch causes the same acceleration, does your speed decreases by 1.5 m/s, more than 1.5 m/s or less than 1.5 m/s? justify your answer with a calculation.

To determine the effect of a sandy patch on your speed when entering it with a lower speed, we need to use the concept of acceleration.

Acceleration is the rate at which an object's velocity changes. It is calculated as the change in velocity divided by the time taken for the change to occur. In this case, the sandy patch causes a decrease in velocity, resulting in a negative acceleration.

From the previous problem, we know that when entering the sandy patch with a speed of 8.5 m/s, the velocity decreases by 1.5 m/s, resulting in an acceleration of -1.5 m/s^2.

Now, let's consider if you enter the sandy patch with a speed of 7.0 m/s. We need to determine the new acceleration and the corresponding decrease in speed.

To calculate the new acceleration, we can use the same formula:

acceleration = change in velocity / time

Using the previous problem's values:

-1.5 m/s^2 = change in velocity / time

The time taken for the velocity change remains the same since we are assuming the sandy patch causes the same acceleration. Therefore, we can rearrange the formula to find the change in velocity:

change in velocity = acceleration * time

change in velocity = -1.5 m/s^2 * time

To find the time, we can use the formula for motion with constant acceleration:

change in velocity = initial velocity * time + (1/2) * acceleration * time^2

Since the initial velocity is 7.0 m/s and the acceleration is -1.5 m/s^2, we have:

change in velocity = 7.0 m/s * time - (1/2) * 1.5 m/s^2 * time^2

Simplifying the equation:

change in velocity = (7.0 m/s - 0.75 m/s^2 * time) * time

Now, we can solve for the time:

0 = (7.0 m/s - 0.75 m/s^2 * time) * time

This equation can be rearranged and solved using various methods, such as factoring, the quadratic formula, or numerical approximation. Once we find the time, we can substitute it back into the equation for change in velocity to get the exact numerical value.

After finding the change in velocity, we can compare it to the change in velocity when entering the sandy patch with a speed of 8.5 m/s. The decrease in speed will be the magnitude of the change in velocity.

Based on this analysis, the conclusion about whether the speed decrease will be more than 1.5 m/s, less than 1.5 m/s, or equal to 1.5 m/s when entering the sandy patch with a lower speed of 7.0 m/s can only be determined by performing the aforementioned calculations.