A solution is prepared by dissolving 0.5842g of oxalic acid (H2C2O4) in enough water to make 100.0ml of solution. A 10.00ml aliquot (portion) of this solution is then diluted to a final volume of 250.0ml. What is the final molarity of thus prepared oxalic acid solution?

The final answer is 10000 ????

To find the final molarity of the oxalic acid solution, we need to calculate the number of moles of oxalic acid present in the 10.00 mL aliquot and then use this to determine the concentration in mol/L.

First, let's calculate the number of moles of oxalic acid in the 0.5842g sample:

Molar mass of H2C2O4 = (2*1.008) + (2*12.01) + (4*16.00) = 90.03 g/mol

Number of moles = 0.5842g / 90.03 g/mol

Next, we convert the mL aliquot to liters:

10.00 mL = 10.00 mL/1000 mL/L = 0.0100 L

Now, we can calculate the molarity (M) of the oxalic acid in the 10.00 mL aliquot:

Molarity (M) = moles of solute (oxalic acid) / volume of solution (L)

M = moles / volume = (0.5842 g / 90.03 g/mol) / 0.0100 L

M = 0.00650 mol / 0.0100 L = 0.650 mol/L

Therefore, the final molarity of the oxalic acid solution is 0.650 mol/L.

To find the final molarity of the oxalic acid solution, we need to calculate the number of moles of oxalic acid in the final 10.00 mL aliquot and then use that to determine the molarity.

Step 1: Calculate the number of moles of oxalic acid in the original solution.
The molar mass of oxalic acid (H2C2O4) is:
2(1.008 g/mol) + 2(12.01 g/mol) + 4(16.00 g/mol) = 90.034 g/mol

To calculate the number of moles in 0.5842 g of oxalic acid, we can use the formula:
moles = mass/molar mass

moles = 0.5842 g / 90.034 g/mol
moles = 0.006492 mol

Step 2: Calculate the final number of moles in the 10.00 mL aliquot.
Since the 10.00 mL aliquot is diluted to a final volume of 250.0 mL, the number of moles will remain the same.

moles = 0.006492 mol

Step 3: Calculate the final molarity.
Molarity is defined as moles of solute divided by the volume of the solution in liters.

Molarity = moles/volume (in liters)

Since the final volume is 250.0 mL, we need to convert it to liters:
250.0 mL ÷ 1000 mL/L = 0.250 L

Molarity = 0.006492 mol / 0.250 L
Molarity = 0.02597 M

Therefore, the final molarity of the prepared oxalic acid solution is 0.02597 M.

moles H2C2O4 = grams/molar mass

moles x (10/100) = moles in 250 mL.
M = moles/0.250 = ??