Posted by Lynn on Friday, November 18, 2011 at 12:32am.
In a volleyball a player on one team spikes the ball over the net when the ball is 10 ft above court. The spike drives the ball downward with initial vertical velocity of 55 feet per second. Players on the opposing team must hit the ball back over the net before it touches the court. How much time do the opposing players have to get ready to hit the spiked ball?
I know that the formula is h=16t^2+v0t+h0
The only thing I know what to do is...
10=16t^255 ? ?

Math  Reiny, Friday, November 18, 2011 at 8:32am
Your formula would be
h = 16t^2  55t + 10
when it hits the ground h = 0
16t^2 + 55t  10 = 0
t = (55 ± √3665)/32 = .173 seconds or a negataive

Math  David, Friday, February 6, 2015 at 1:21am
10ft

Math  David, Friday, February 6, 2015 at 1:26am
set up as a quadratic then solve for t
0=(8.98)t^2+55t10
t=0.1767 seconds
Answer This Question
Related Questions
 Physics  A regulation volleyball court is L = 18.0 m long and a regulation ...
 physics  For women's volleyball the top of the net is 2.24 m above the floor ...
 Physics  A regulation volleyball court is L = 18.0 m long and a regulation ...
 Physics  A regulation volleyball court is L = 18.0 m long and a regulation ...
 Physics repost  A regulation volleyball court is L = 18.0 m long and a ...
 PHYSICS  During a tennis match a player serves the ball at 23.6 m/s with the ...
 algebra 2  A player bumps a volleyball with an initial vertical velocity of 20 ...
 Math  You throw a ball into the air with an initial vertical velocity of 31 ...
 Quadratic Relations, Algebra, Math  URGENT!! PLEASE HELP In a volleyball match...
 Trigonometry  A volleyball player spikes the ball from a height of 2.44 meters...
More Related Questions