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December 21, 2014

December 21, 2014

Posted by **Betty** on Thursday, November 17, 2011 at 11:55pm.

- calculus -
**Steve**, Friday, November 18, 2011 at 1:32pmv = pi r^2 h

a = 2 pi r^2 + 2 pi r h

h = 16pi/pi r^2 = 16/r^2

a = 2 pi r^2 + 2 pi r 16/r^2

= 2pi (r^2 + 16/r)

min area when 2r - 16/r^2 = 0

2r^3 - 16 = 0

r = 2

So, the can has a radius of 2 and a height of 4

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