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January 31, 2015

January 31, 2015

Posted by **Tomtom** on Thursday, November 17, 2011 at 6:52pm.

a)Find the value of the discriminant.

b)Use any method to find the real roots of the equation if they exist.

2x^2+7x=0

- Trigonometry -
**Steve**, Friday, November 18, 2011 at 12:05pmsurely you got as far as evaluating the discriminant: b^2 - 4ac = 7 - 0 = 7

factor: x(2x+7) = 0

a product is zero if any factor is zero. So,

x=0 or (2x+7) = 0

so, the roots are 0 and -7/2

Using the quadratic formula, we have

x = [-7 +/- sqrt(49-0)]/4

= [-7 +/- 7]/2

= 0 or -7/2

Completing the square,

2(x^2 + 7/2 x + (7/4)^2) - 2(7/4)^2 = 0

2(x + 7/4)^2 = 2(7/4)^2

x + 7/4 = (7/4)^2 = 49/16

x = -7/4 +/- 7/4

= 0 or -7/2

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