Thursday
March 23, 2017

Post a New Question

Posted by on Thursday, November 17, 2011 at 5:59pm.

A 3.28-kg bucket is attached to a disk-shaped pulley of radius 0.108 m and mass 0.727 kg.

(a) If the bucket is allowed to fall, what is its linear acceleration?

(b) What is the angular acceleration of the pulley?

(c) How far does the bucket drop in 1.65 s?

  • physics - , Thursday, November 17, 2011 at 6:21pm

    T = tension in line

    free body of bucket (Positive is down):
    mg - T = m a

    free body of pulley:
    acceleration a = angular acceleration alpha * r

    alpha = moment/I
    I = (1/2) m r^2 =
    moment = T r
    so
    alpha = 2 T r/ m r^2 = 2 T/m r
    a = alpha r = 2 T/m
    therefore
    mg - T = m a but a = 2 T/m
    so
    m g - T = 2T
    T = m g/3
    now go back and get a and alpha etc

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question