A 3.28-kg bucket is attached to a disk-shaped pulley of radius 0.108 m and mass 0.727 kg.
(a) If the bucket is allowed to fall, what is its linear acceleration?
(b) What is the angular acceleration of the pulley?
(c) How far does the bucket drop in 1.65 s?
physics - Damon, Thursday, November 17, 2011 at 6:21pm
T = tension in line
free body of bucket (Positive is down):
mg - T = m a
free body of pulley:
acceleration a = angular acceleration alpha * r
alpha = moment/I
I = (1/2) m r^2 =
moment = T r
alpha = 2 T r/ m r^2 = 2 T/m r
a = alpha r = 2 T/m
mg - T = m a but a = 2 T/m
m g - T = 2T
T = m g/3
now go back and get a and alpha etc