a ball is thrown up vertically and caught at 9.3 sec. what is the intial velocity

hf=hi+vi*t- 4.9 t^2

0=0+Vi*9.3-4.9*9.3^2 solve for vi

is the answer 386.556??

No. You can do better than that.

whats the answer?

You have come to the wrong place to mooch answers. You learn nothing doing that.

Solve this: 0=Vi*9.3-4.9*9.3^2

423.801?

i got the same question, however how would you determine the maximum hieght it reaches?

The time to get to the top is 1/2 * 9.3sec

hf=ho+Vi*(1/2*9.3)-4.9(1/2*9.3)^2

ho=0, vi you solved for, find hf.

No, anonomus.

vi*9.3= 4.9*9.3^2
surely you can solve this equation.
It is less than 50m/s

45.57!

thankyou bob. i calculated the problem and got roughly 106 m.