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December 18, 2014

December 18, 2014

Posted by **lisa** on Thursday, November 17, 2011 at 12:55pm.

- algebra -
**Henry**, Saturday, November 19, 2011 at 4:12pmVf = X mi/h.=Velocity of freight train.

Vp = (X + 18)mi/h = Velocity of passenger train.

Eq1: Dp = (X+18)t = 260.

Eq2: Df = Xt = 170,

t = 170/X.

In Eq1, substitute 170/X for t:

(X+18)170/X = 260,

Multiply both sides by X:

170(X+18) = 260x,

170x + 3060 = 260x,

260x - 170x = 3060,

90x = 3060,

X = 34 mi/h = Speed of freight train.

X+18 = 34 + 18 = 52 = Speed of passenger train.

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