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Posted by on Wednesday, November 16, 2011 at 11:57pm.

in an experiment 5.00ml of 0.1440 mol L^1- aqueos KIO3 was reacted with an excess of aqueous iodide and the molecular iodine I2, Formed was titrated against 0.1000mol L^1- aqueous S2O3^2- the equation for the titration reaction is:
I2(aq)+ 2 S2O3^2-(aq)---->S4O6^2-(aq)+ 2I^-1(aq)

calculate the numbers of moles of sodium thiosulfate (Na2S2O3) and hence the moles of S2O3^2- ions present in the volume of 43mL

that is all the information i have. Can someone explain to me how to do it?

  • chemistry - , Thursday, November 17, 2011 at 12:18am

    You've picked the problem apart. Your first post (five posts ago, should have had all of the problem and that would have made things simpler for you). As it stands, you're still not at the end. But here goes, for these two parts anyway.
    moles KIO3 = M KIO3 x L KIO3 = ?

    The last part of the problem you asked is for moles S2O3^2-. That is moles S2O3^2-= M S2O3^2- x L S2O3^2- = y moles S2O3^2-

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