is 4y(squared)-17y+15 factorable?
i think its just not factorable, but i'm not sure. thank you::)
let 4y^2 - 17y + 15 = 0
If the discriminant is a perfect square, then the quadratic will factor
b^2 - 4ac = 17^2 - 4(4)(15) = 49
yes it will factor.
(y-3)(4y - 5)
4x^3 + 8x^2y - 5xy^2
To determine if the quadratic trinomial 4y^2 - 17y + 15 is factorable, we can apply the factoring techniques.
First, we check if the trinomial can be factored using the ac method. The ac method involves finding two numbers whose product is equal to the product of the coefficient of the y^2 term (a) and the constant term (c), and whose sum is equal to the coefficient of the y term (b).
For the given quadratic trinomial 4y^2 - 17y + 15, the coefficient of the y^2 term is 4, and the constant term is 15. The product of 4 and 15 is 60. Now we need to find two numbers that satisfy these conditions and add up to -17, the coefficient of the y term.
After trying different number combinations, we find that -12 and -5 satisfy these conditions. The sum of -12 and -5 is indeed -17, which means we can rewrite the y term as -12y - 5y. Thus, we can factor the trinomial as:
4y^2 - 17y + 15 = (4y - 5)(y - 3)
Therefore, the quadratic trinomial 4y^2 - 17y + 15 is indeed factorable into (4y - 5)(y - 3).