Posted by ian on .
An airplane passenger carries a 250 N suitcase up the stairs, a displacement of 4.70 m vertically, and 5.30 m horizontally.
How much work does the passenger do?
For the Vertical work:
W = F.d => W = 250*4.70*cos(theta) where tan(theta) = 4.7/5.3 . Do the math :)
Fro the Horizontal work:
W = F.d => W = 250*5.30*sin(theta) where tan(theta) = 4.7/5.3 . Do the math :)
*find theta using tan inverse and then find the cos and sin of the theta to use in the above equations