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March 1, 2015

March 1, 2015

Posted by **ian** on Wednesday, November 16, 2011 at 10:25pm.

How much work does the passenger do?

- physics -
**Anonymous**, Thursday, November 17, 2011 at 2:59pmFor the Vertical work:

W = F.d => W = 250*4.70*cos(theta) where tan(theta) = 4.7/5.3 . Do the math :)

Fro the Horizontal work:

W = F.d => W = 250*5.30*sin(theta) where tan(theta) = 4.7/5.3 . Do the math :)

*find theta using tan inverse and then find the cos and sin of the theta to use in the above equations

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