Had The Same Teacher For Physics And Ughh I Am Stuck. Notes Help Me A Lot So If Anyone Could Write A Few Or A Bunch Out That Would Be Awesome. I Am Not The Type Of A Person Who Minds Writing Down Notes;)
Teacher Told Us About Work And That The Formula For It Is W = Fd. IS It?
Then We Also Got Told About Power. And Formula For That Is. W/t. W is Fd So Have To Do More Work Here To Get The Answer.
I Also Managed To Do Some Questions But Want To Make Sure I Did Them Right.
A force of 825 N is needed to push a car across a lot. Two students push the car 35m.
A. How much work is done?
B. After a rainstorm, the force needed to push the car doubled because the ground became soft. By what amount does the work done by the students change?
A. 28875J
B. 57750J
A delivery clerk carries a 34-N package from the ground to the fifth floor of an office building, a total height of 15m. How much work is done by the clerk?
Would it be zero??
What work is done by a fork life raising a 583-kg box 1.2m?
W = fd
W = (5719)(1.2)
W = 6863J
And If You're Wondering How I Got The Force Well I Multiplied Mass By Gravity.
U And A Friend each carry identical boxes to a room one floor above you and down the hall. U choose to carry it first up the stairs, then down the hall. Your friend carries it down the hall, then up another stairwell? Who does more work?
I think they both do the same amount of work just during different times..
Yes, the formula for work is indeed W = Fd, where W represents work, F represents force, and d represents distance. To calculate the amount of work done, you multiply the force applied to an object with the distance over which it is applied.
Let's go through each of the questions you have mentioned:
1. A force of 825 N is needed to push a car across a lot for a distance of 35 m. To find the work done, use the formula W = Fd. So, W = (825 N) * (35 m) = 28,875 J (Joules).
2. After the rainstorm, the force needed to push the car doubled, so the new force required is 2 * 825 N = 1650 N. The work done by the students changed, so you need to find the difference between the initial and final work done. ΔW = (1650 N) * (35 m) - (825 N) * (35 m) = 57,750 J.
3. The work done by the delivery clerk in carrying a 34-N package up to the fifth floor of a building is not zero. To calculate the work done, use the formula W = Fd. W = (34 N) * (15 m) = 510 J. Therefore, 510 J of work is done by the clerk.
4. You correctly calculated the work done by a forklift in raising a 583-kg box by multiplying the force (weight) with the distance. W = (583 kg * 9.8 m/s^2) * (1.2 m) = 6863 J.
Regarding the last question, you are correct. Both you and your friend do the same amount of work but in different orders. The work done does not depend on the order in which the work is done, as long as the distance and force are the same.
I hope this helps! If you have any more questions or need further assistance, feel free to ask.