the solubility of Kl is 50g in 100g of H2O at 20 celcius, if 110g of Kl are added to 220g of H2O, is the soultion saturated or unsaturated?
and what is the %m/m of the solution?
Solubility is 50 g KI/100 g H2O; how much water will it take to dissolve 110 g KI? That will be 100 g H2O x (110mL/50mL) = 220 g H2O. The solution is saturated since that is what it will hold but no more.
110 g KI/220 g H2O is
110 g KI/(220gH2O + 110g KI) = 110/(330g soln).
% w/w = (110 g KI/330 g soln) * 100 = ??
791j
A saturated solution will form
To determine whether the solution is saturated or unsaturated, we need to compare the amount of solute (Kl) present in the solution (110g) with its solubility at that temperature (50g in 100g of H2O).
To solve this, we can follow these steps:
Step 1: Calculate the total mass of the solution.
Total mass of the solution = mass of solute + mass of solvent = 110g Kl + 220g H2O = 330g
Step 2: Calculate the solute-to-solvent ratio.
Solute-to-solvent ratio = mass of solute / mass of solvent
Solute-to-solvent ratio = 110g Kl / 220g H2O = 0.5
Step 3: Compare the solute-to-solvent ratio with the solubility ratio.
The solubility ratio of Kl at 20 degrees Celsius is 50g Kl / 100g H2O = 0.5
Since the solute-to-solvent ratio (0.5) is equal to the solubility ratio (0.5), the solution is saturated. This means that the solution contains the maximum amount of solute that can be dissolved at that temperature.
To calculate the percent mass/mass (%m/m) of the solution, we need to determine the mass of Kl in the solution and divide it by the total mass of the solution. Then we can multiply the result by 100.
Step 4: Calculate the mass of Kl in the solution.
Mass of Kl in the solution = 110g
Step 5: Calculate the percent mass/mass (%m/m) of the solution.
%m/m = (mass of Kl in the solution / total mass of the solution) x 100
%m/m = (110g / 330g) x 100
%m/m = 33.33%
Therefore, the solution is saturated, and the percent mass/mass (%m/m) of the solution is 33.33%.